Pembahasan:
1.
P = e σ A T4
= 1 . 5,67 x 10-8 . 0,5 x
10-4 . 30004
= 22,96 joule
2.
P = e σ A T4
= 1 .
5,67 x 10-8 . 0,2
. 4734
= 5,6
x 102
joule
3.
Λ = 
= 
=
0,82
x 10-5
m
4.
Λ =
= 
=
7.25
2 x 10-5 m
5.
E = h
160x10-19 = 6,6 .10-34
. 
Λ =
1,24 A
6.
T1
= 27oC = 300
K
T2 = 127oC = 400 K
P2/P1 = (T2/T1)4
P2/P1 = (400/300)4 = (4/3)4 = 256 : 81
T2 = 127oC = 400 K
P2/P1 = (T2/T1)4
P2/P1 = (400/300)4 = (4/3)4 = 256 : 81
7.
σ
= 5,67 x 10−8 W/mK4
T =27oC = 300 K
e = 1
A = 100 cm2 = 100 x 10−4 = 10−2
T =27oC = 300 K
e = 1
A = 100 cm2 = 100 x 10−4 = 10−2
laju rata-rata:
P = e σ T 4A
P = (1)(5,67 x 10−8 )(300)4(10−2)
P = 45,93 joule/s
P = (1)(5,67 x 10−8 )(300)4(10−2)
P = 45,93 joule/s
8.
laju
rata-rata:
P = e σ T 4A
P = (1)(5,67 x 10−8 )(500)4(5 x 10−2)
P = 17,71 joule/s
P = (1)(5,67 x 10−8 )(500)4(5 x 10−2)
P = 17,71 joule/s
9.
Daya radiasi yang dipancarkan sekarang :
P2/P1 = (T2/T1)4
P2/P1 = (400/300)4
P2 = (400/300)4 x P1
P2 = (256/81) x 200
P2/P1 = (T2/T1)4
P2/P1 = (400/300)4
P2 = (400/300)4 x P1
P2 = (256/81) x 200
=
(256/81) x 200 = 632 watt
10. λmaks T = C
λmaks (273) = 2,898 x 10−3
λmaks = 10,62 x 10−6 m
λmaks (273) = 2,898 x 10−3
λmaks = 10,62 x 10−6 m
11. λmaks T = C
λmaks (300)= 2,898 x 10−3
λmaks = 9,66 x 10−3 m
λmaks (300)= 2,898 x 10−3
λmaks = 9,66 x 10−3 m
12. λmaks 2 T2 = λmaks
1 T1
λmaks 2 (5/3 T) = 5000 Å (T)
λmaks 2 = (3/5) x 5000 Å = 3000 Å
λmaks 2 (5/3 T) = 5000 Å (T)
λmaks 2 = (3/5) x 5000 Å = 3000 Å
13.
P1 =
= 
2 x
4
2 x
4
= 
2 x
4
2 x
4
= 9 x 1 / 18
= 9 : 18
14.
s = 
s = 
s = 9 x 108
15. E
= P t
n h f
= P t
n h c/Λ = P t
n 6,6 x 10-34 . 
= 30
= 30
n 19,8 x 10-26 = 16800 . 10-5
n =
85 . 1019
16. A = keliling x
tinggi + 2 luas
permukaan
= 2 
= 2 x 3,14 x 5 x
10-4 x 0,05 + 2 x
3,14 (5 x 10-4
)2
= 2, 8 x 10-6
17. P =
e σ A T4
= 1. 2,8
x 10-6. 5,67
x 10-8
(500)4
=99255 x
10-6
18. λmaks =
=
=
0,63 . 10-5 m
19.
P = V.I
= 230 x 0,2
= 46 watt
20. λmaks =
0,6.105 = 2,98.10-3/T
T =
496 K
=
223 °C
21. Δλ = λ’-λ
= 7500 – 2750
= 4750 amstrong
22.
= 
=
= 1,1 x 10-11
23.
f = 
= 
=
= 1,4 x 10 18
Hz
24. E =
h f
=
6,625 . 10-34 x 5.1011
=
33,1
. 10-23 J
25. Λ =
=
=2184 amstrong
26.
T = C/
= 2,898 10-3
/ 4 x 10-6
= 724 K
27. P =
h/Λ
=
6,625.10-34/90
=
7,36.10-36 kg m/s
28. λ
= 
h = 2,93 x 10-10 m
29. Λ =
h/mc
c/f =
h/mc
mc2 =
hf
m =
hf/c2
λT
= 2,898 x 10-3
Sehingga panjang gelombangnya adalah
λ
= 3,29 x 104A
Pembahasan:
1.
P = e σ A T4
= 1 . 5,67 x 10-8 . 0,5 x
10-4 . 30004
= 22,96 joule
2.
P = e σ A T4
= 1 .
5,67 x 10-8 . 0,2
. 4734
= 5,6
x 102
joule
3.
Λ =
=
=
0,82
x 10-5
m
4.
Λ =
=
=
7.25
2 x 10-5 m
5.
E = h
160x10-19 = 6,6 .10-34
.
Λ =
1,24 A
6.
T1
= 27oC = 300
K
T2 = 127oC = 400 K
P2/P1 = (T2/T1)4
P2/P1 = (400/300)4 = (4/3)4 = 256 : 81
T2 = 127oC = 400 K
P2/P1 = (T2/T1)4
P2/P1 = (400/300)4 = (4/3)4 = 256 : 81
7.
σ
= 5,67 x 10−8 W/mK4
T =27oC = 300 K
e = 1
A = 100 cm2 = 100 x 10−4 = 10−2
T =27oC = 300 K
e = 1
A = 100 cm2 = 100 x 10−4 = 10−2
laju rata-rata:
P = e σ T 4A
P = (1)(5,67 x 10−8 )(300)4(10−2)
P = 45,93 joule/s
P = (1)(5,67 x 10−8 )(300)4(10−2)
P = 45,93 joule/s
8.
laju
rata-rata:
P = e σ T 4A
P = (1)(5,67 x 10−8 )(500)4(5 x 10−2)
P = 17,71 joule/s
P = (1)(5,67 x 10−8 )(500)4(5 x 10−2)
P = 17,71 joule/s
9.
Daya radiasi yang dipancarkan sekarang :
P2/P1 = (T2/T1)4
P2/P1 = (400/300)4
P2 = (400/300)4 x P1
P2 = (256/81) x 200
P2/P1 = (T2/T1)4
P2/P1 = (400/300)4
P2 = (400/300)4 x P1
P2 = (256/81) x 200
=
(256/81) x 200 = 632 watt
10. λmaks T = C
λmaks (273) = 2,898 x 10−3
λmaks = 10,62 x 10−6 m
λmaks (273) = 2,898 x 10−3
λmaks = 10,62 x 10−6 m
11. λmaks T = C
λmaks (300)= 2,898 x 10−3
λmaks = 9,66 x 10−3 m
λmaks (300)= 2,898 x 10−3
λmaks = 9,66 x 10−3 m
12. λmaks 2 T2 = λmaks
1 T1
λmaks 2 (5/3 T) = 5000 Å (T)
λmaks 2 = (3/5) x 5000 Å = 3000 Å
λmaks 2 (5/3 T) = 5000 Å (T)
λmaks 2 = (3/5) x 5000 Å = 3000 Å
13.
P1 =
= 2 x
4
2 x
4
= 2 x
4
2 x
4
= 9 x 1 / 18
= 9 : 18
14.
s =
s =
s = 9 x 108
15. E
= P t
n h f
= P t
n h c/Λ = P t
n 6,6 x 10-34 . = 30
= 30
n 19,8 x 10-26 = 16800 . 10-5
n =
85 . 1019
16. A = keliling x
tinggi + 2 luas
permukaan
= 2
= 2 x 3,14 x 5 x
10-4 x 0,05 + 2 x
3,14 (5 x 10-4
)2
= 2, 8 x 10-6
17. P =
e σ A T4
= 1. 2,8
x 10-6. 5,67
x 10-8
(500)4
=99255 x
10-6
18. λmaks =
=
=
0,63 . 10-5 m
19.
P = V.I
= 230 x 0,2
= 46 watt
20. λmaks =
0,6.105 = 2,98.10-3/T
T =
496 K
=
223 °C
21. Δλ = λ’-λ
= 7500 – 2750
= 4750 amstrong
22.
=
=
= 1,1 x 10-11
23.
f = =
=
= 1,4 x 10 18
Hz
24. E =
h f
=
6,625 . 10-34 x 5.1011
=
33,1
. 10-23 J
25. Λ =
=
=2184 amstrong
26.
T = C/
= 2,898 10-3
/ 4 x 10-6
= 724 K
27. P =
h/Λ
=
6,625.10-34/90
=
7,36.10-36 kg m/s
28. λ
=
h = 2,93 x 10-10 m
29. Λ =
h/mc
c/f =
h/mc
mc2 =
hf
m =
hf/c2
λT
= 2,898 x 10-3
Sehingga panjang gelombangnya adalah
λ
= 3,29 x 104A
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